0.00012=(2x)^2/(1-x)(1-x)

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Solution for 0.00012=(2x)^2/(1-x)(1-x) equation:


D( x )

1-x = 0

1-x = 0

1-x = 0

1-x = 0 // - 1

-x = -1 // * -1

x = 1

x in (-oo:1) U (1:+oo)

0.00012 = (((2*x)^2)/(1-x))*(1-x) // - (((2*x)^2)/(1-x))*(1-x)

0.00012-((((2*x)^2)/(1-x))*(1-x)) = 0

0.00012-(2*x)^2 = 0

-4*x^2 = -0.00012 // : -4

x^2 = 0.00003

x^2 = 0.00003 // ^ 1/2

abs(x) = 0.00003^(1/2)

x = 0.00003^(1/2) or x = -0.00003^(1/2)

x in { 0.00003^(1/2), -0.00003^(1/2) }

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